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Question
The oxidation number of phosphorous in Ba(H2PO2)2 is ______.
Options
- 3
+ 3
+ 5
+ 1
MCQ
Fill in the Blanks
Solution
The oxidation number of phosphorous in Ba(H2PO2)2 is + 1.
Explanation:
Ba(H2PO2)2
O.S. (Ba) + O.S. (4H) + O.S. (2P) + O.S. (4O) = 0
2 + 4 + 2P + (- 8) = 0
2P - 2 = 0
2P = + 2 ∴ P = + 1
Oxidation State of P = + 1
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Oxidation Number
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