Advertisements
Advertisements
प्रश्न
The perimeter of a rectangle is 40 m. Its length is four metres less than five times its breadth. Find the area of the rectangle.
उत्तर
Let breadih of the rectangle = x
Then, length of the rectangle = 5x – 4
We know that,
Perimeter of rectangle = 2(l + b)
⇒ 40 = 2(l + b) ......[∵ Perimeter = 40 m, given]
⇒ 40 = 2(5x – 4 + x)
⇒ 40 = 2(6x – 4)
⇒ 12x – 8 = 40
⇒ 12x = 40 + 8
⇒ 12x = 48
⇒ x = `48/12` = 4
So, breadth = x = 4 m and length = 5x – 4 = 5 × 4 – 4 = 16 m
∴ Area of rectangle = l × b = 4 × 16 = 64 m2
Hence, the area of rectangle is 64 m2.
APPEARS IN
संबंधित प्रश्न
If the side of a square is tripled, how many times the perimeter of the first square will that of the new square be?
If the side of a square is tripled, how many times will its area be as compared to the area of the original square?
Find the area of a rectangle whose length and breadth are 12 cm and 4 cm respectively.
Find the area in square metre of a piece of cloth 1m 25 cm wide and 2 m long.
Find the area of the rectangle whose sides are:
2 km and 3 km
The length and breadth of a rectangle are as given below:
9m and 6m
Split the following shape into rectangle and find their area. (The measures are given in centimetres).
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are:
100 cm and 144 cm
People of Khejadli village take good care of plants, trees and animals. They say that plants and animals can survive without us, but we can not survive without them. Inspired by her elders Amrita marked some land for her pets (camel and ox) and plants. Find the ratio of the areas kept for animals and plants to the living area.
4 squares each of side 10 cm have been cut from each corner of a rectangular sheet of paper of size 100 cm × 80 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 10 cm length. Find the area of the remaining part of the paper.