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प्रश्न
The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
पर्याय
25 m
37 m
50 m
100 m
उत्तर
100 m
For the same u range, \[R \propto \sin\left( 2\theta \right)\] .
So, \[\frac{R_1}{R_2} = \frac{\sin\left( 2 \theta_1 \right)}{\sin\left( 2 \theta_2 \right)}\]
\[\Rightarrow R_2 = 50 \times \frac{\sin\left( 90 \right)}{\sin\left( 30 \right)} = 100 \text{ m } \]
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