Question

The reaction \[\ce{A + B -> P}\], is second order in A and first order in B. What is the rate law for the reaction?

पर्याय

• Rate = k[A] [B]

• Rate = k[A]² [B]^1/2

• Rate = k[A]² [B]

• Rate = k[A] [B]²

Answer 1

Rate = k[A]² [B]

Explanation:

∵ The order of A is second and order of B is first, therefore the rate law becomes

Rate = k[A]² [B]