Advertisements
Advertisements
Question
The reaction \[\ce{A + B -> P}\], is second order in A and first order in B. What is the rate law for the reaction?
Options
Rate = k[A] [B]
Rate = k[A]2 [B]1/2
Rate = k[A]2 [B]
Rate = k[A] [B]2
MCQ
Solution
Rate = k[A]2 [B]
Explanation:
∵ The order of A is second and order of B is first, therefore the rate law becomes
Rate = k[A]2 [B]
shaalaa.com
Rate of Reaction and Reactant Concentration
Is there an error in this question or solution?
