Question

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCI solution at 298 K is 0.146 × 10⁻³ S cm⁻¹?

पर्याय

• 0.219 cm⁻¹

• 0.25 cm⁻¹

• 1.02 cm⁻¹

• 0.973 cm⁻¹

Answer 1

0.219 cm⁻¹

Explanation:

Cell constant = k × R

= 0.146 × 10⁻³ × 1500

= 0.219 cm⁻¹