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Question
The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCI solution at 298 K is 0.146 × 10−3 S cm−1?
Options
0.219 cm−1
0.25 cm−1
1.02 cm−1
0.973 cm−1
MCQ
Solution
0.219 cm−1
Explanation:
Cell constant = k × R
= 0.146 × 10−3 × 1500
= 0.219 cm−1
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Electrical Conductance of Solution
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