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प्रश्न
The short wavelength limit for the Lyman series of the hydrogen spectrum is 913.4 Å. Calculate the short wavelength limit for the Balmer series of the hydrogen spectrum.
उत्तर
Given short wavelength limit of the Lyman series
`1/λ_"L" = "R"(1/1^2 - 1/∞)`
`1/(913.4 Å) = "R"(1/1^2 - 1/∞)`
λL = `1/"R"` = 913.4 Å
For the short wavelength limit of Balmer series
n1 = 2, n2 = ∞
`1/λ_"B" = "R"(1/2^2 - 1/∞)`
λB = `4/"R"`
= 4 × 913.4 Å
= 3653.6 Å
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