Advertisements
Advertisements
Question
The short wavelength limit for the Lyman series of the hydrogen spectrum is 913.4 Å. Calculate the short wavelength limit for the Balmer series of the hydrogen spectrum.
Solution
Given short wavelength limit of the Lyman series
`1/λ_"L" = "R"(1/1^2 - 1/∞)`
`1/(913.4 Å) = "R"(1/1^2 - 1/∞)`
λL = `1/"R"` = 913.4 Å
For the short wavelength limit of Balmer series
n1 = 2, n2 = ∞
`1/λ_"B" = "R"(1/2^2 - 1/∞)`
λB = `4/"R"`
= 4 × 913.4 Å
= 3653.6 Å
APPEARS IN
RELATED QUESTIONS
The nuclei having same number of protons but different number of neutrons are called ___ .
(a) isobars
(b) a-particles
(c) isotopes
(d) y-particles
The ground state energy of hydrogen atom is – 13∙6 eV. If an electron makes a transition from an energy level – 1∙51 eV to – 3∙4 eV, calculate the wavelength of the spectral line emitted and name the series of hydrogen spectrum to which it belongs.
Using Rydberg formula, calculate the longest wavelength belonging to Lyman and Balmer series. In which region of hydrogen spectrum do these transitions lie?
[Given R = 1.1 ✕ 107 m−1]
The ground state energy of hydrogen atom is −13.6 eV. If and electron make a transition from the energy level −0.85 eV to −3.4 eV, calculate spectrum does his wavelength belong?
Hydrogen spectrum consists of discrete bright lines in a dark background and it is specifically known as hydrogen emission spectrum. There is one more type of hydrogen spectrum that exists where we get dark lines on the bright background, it is known as absorption spectrum. Balmer found an empirical formula by the observation of a small part of this spectrum and it is represented by
`1/lambda = "R"(1/2^2 - 1/"n"^2)`, where n = 3, 4, 5,....
For Lyman series, the emission is from first state to nth state, for Paschen series, it is from third state to nth state, for Brackett series, it is from fourth state to nth state and for P fund series, it is from fifth state to nth state.
Number of spectral lines in hydrogen atom is ______.
Hydrogen spectrum consists of discrete bright lines in a dark background and it is specifically known as hydrogen emission spectrum. There is one more type of hydrogen spectrum that exists where we get dark lines on the bright background, it is known as the absorption spectrum. Balmer found an empirical formula by the observation of a small part of this spectrum and it is represented by
`1/lambda = "R"(1/2^2 - 1/"n"^2)`, where n = 3, 4, 5,....
For Lyman series, the emission is from first state to nth state, for Paschen series, it is from third state to nth state, for Brackett series, it is from fourth state to nth state and for P fund series, it is from fifth state to nth state.
Which series of hydrogen spectrum corresponds to ultraviolet region?
Hydrogen spectrum consists of discrete bright lines in a dark background and it is specifically known as hydrogen emission spectrum. There is one more type of hydrogen spectrum that exists where we get dark lines on the bright background, it is known as absorption spectrum. Balmer found an empirical formula by the observation of a small part of this spectrum and it is represented by
`1/lambda = "R"(1/2^2 - 1/"n"^2)`, where n = 3, 4, 5,....
For Lyman series, the emission is from first state to nth state, for Paschen series, it is from third state to nth state, for Brackett series, it is from fourth state to nth state and for P fund series, it is from fifth state to nth state.
Rydberg constant is ______.
In the following atoms and molecules for the transition from n = 2 to n = 1, the spectral line of minimum wavelength will be produced by
An electron in a hydrogen atom makes transitions from orbits of higher energies to orbits of lower energies.
- When will such transitions result in (a) Lyman (b) Balmer series?
- Find the ratio of the longest wavelength in the Lyman series to the shortest wavelength in the Balmer series.
A particular hydrogen-like ion emits radiation of frequency 2.92 × 1015 Hz when it makes the transition from n = 3 to n = 1. The frequency in Hz of radiation emitted in transition from n = 2 to n = 1 will be ______.
