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प्रश्न
The sides of a triangle are x2 – 3xy + 8, 4x2 + 5xy – 3 and 6 – 3x2 + 4xy. Find its perimeter.
उत्तर
Required perimeter = Sum of three sides
= x2 − 3xy + 8 + 4x2 + 5xy − 3 + 6 − 3x2 + 4xy
= x2 + 4x2 − 3x2 − 3xy + 5xy + 4xy + 8 − 3 + 6
= 2x2 + 6xy + 11
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संबंधित प्रश्न
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The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.
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