Advertisements
Advertisements
प्रश्न
What must be subtracted from 19x4 + 2x3 + 30x – 37 to get 8x4 + 22x3 – 7x – 60 ?
उत्तर
The required result will be
(19x4 + 2x3 + 30x – 37) − (8x4 + 22x3 – 7x – 60)
= 19x4 + 2x3 + 30x – 37 − 8x4 + 22x3 + 7x + 60
= 11x4 – 20x3 + 37x + 23
APPEARS IN
संबंधित प्रश्न
Evaluate :
3x2 + 5xy − 4y2 + x2 − 8xy − 5y2
Add : a − 3b + 3; 2a + 5 − 3c; 6c − 15 + 6b
Subtract : x3 − 4x − 1 from 3x3 − x2 + 6
Subtract : a2 + ab + b2 from 4a2 − 3ab + 2b2
Take away – 3x3 + 4x2 – 5x+ 6 from 3x3 – 4x2 + 5x – 6
Take m2 + m + 4 from −m2 + 3m + 6 and the result from m2 + m + 1.
What must be added to x4 – x3 + x2 + x + 3 to obtain x4 + x2 – 1 ?
The sides of a triangle are x2 – 3xy + 8, 4x2 + 5xy – 3 and 6 – 3x2 + 4xy. Find its perimeter.
The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.
How much smaller is 15x – 18y + 19z than 22x – 20y – 13z + 26 ?