Advertisements
Advertisements
प्रश्न
The sum of first n terms of an A.P. is 3n2 + 4n. Find the 25th term of this A.P.
उत्तर
We know
\[a_n = S_n - S_{n - 1} \]
\[ \therefore a_n = 3 n^2 + 4n - 3 \left( n - 1 \right)^2 - 4\left( n - 1 \right)\]
\[ \Rightarrow a_n = 6n + 1\]
APPEARS IN
संबंधित प्रश्न
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on. In how many rows are the 200 logs placed, and how many logs are in the top row?
The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP.
If (m + 1)th term of an A.P is twice the (n + 1)th term, prove that (3m + 1)th term is twice the (m + n + 1)th term.
Find the sum of the following arithmetic progressions: 50, 46, 42, ... to 10 terms
The 8th term of an AP is zero. Prove that its 38th term is triple its 18th term.
If the sum of a certain number of terms starting from first term of an A.P. is 25, 22, 19, ..., is 116. Find the last term.
If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =
Obtain the sum of the first 56 terms of an A.P. whose 18th and 39th terms are 52 and 148 respectively.
In a ‘Mahila Bachat Gat’, Sharvari invested ₹ 2 on first day, ₹ 4 on second day and ₹ 6 on third day. If she saves like this, then what would be her total savings in the month of February 2010?
The ratio of the 11th term to the 18th term of an AP is 2 : 3. Find the ratio of the 5th term to the 21st term, and also the ratio of the sum of the first five terms to the sum of the first 21 terms.