Advertisements
Advertisements
प्रश्न
The sum of the square of 2 consecutive odd positive integers is 290.Find them.
उत्तर
Let the numbers be X and X+ 2. Then as per question,
X2 + (X+ 2)2= 290
⇒ 2x2 + 4X - 286 = 0
⇒ X2 + 2X - 143 = 0
⇒ X2 + 13X - 11X -143 = 0
⇒ X (X +13)-11(X +13) = 0
⇒ (X+13 )(X-11) = 0. X can't be negative number as its natural number.
Hence, X = 11and X+ 2= 13.
APPEARS IN
संबंधित प्रश्न
A two digits number is such that the product of the digits is 12. When 36 is added to the number, the digits inter change their places determine the number.
Solve the following quadratic equations by factorization:
`(2x – 3)^2 = 49`
Find the two consecutive positive even integers whose product is 288.
Divide 57 into two parts whose product is 680.
If one of the equation ax2 + bx + c = 0 is three times times the other, then b2 : ac =
If one root of the equation 4x2 − 2x + (λ − 4) = 0 be the reciprocal of the other, then λ =
The area of the isosceles triangle is 60 cm2, and the length of each one of its equal side is 13cm. Find its base.
An aeroplane travelled a distance of 400 km at an average speed of x km/hr. On the return journey the speed was increased by 40 km/hr. Write down the expression for the time taken for
the return Journey. If the return journey took 30 minutes less than the onward journey write down an equation in x and find its value.
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
If x = 3 is one root of the quadratic equation 2x2 + px + 30 = 0, find the value of p and the other root of the quadratic equation.
