Advertisements
Advertisements
प्रश्न
The table given below contains some measures of the right angled triangle. Find the unknown values.
Base | Height | Area |
? | 12 m | 24 sq.m |
उत्तर
Area of the right triangle = `1/2 xx ("base" xx "height") "unit"^2`
24 = `1/2 xx "b" xx 12 "m"^2`
Base = `(24 xx 2)/12` m
= 4 m
Base = 4 m
Tabulating the unknown values
Base | Height | Area |
4 m | 12 m | 24 sq.m |
APPEARS IN
संबंधित प्रश्न
Find values of k if area of triangle is 4 square units and vertices are (−2, 0), (0, 4), (0, k)
Find the area of the following triangle:
Find the area of the following triangle:
Find the third vertex of a ΔABC if two of its vertices are B(-3,1) and C (0,-2) and its centroid is at the origin
Find the area of Δ ABC whose vertices are:
A (1,2) B (-2,3) and C (-3,-4)
Show that the following points are collinear:
(i) A(2,-2), B(-3, 8) and C(-1, 4)
Show that the following points are collinear:
A(5,1), B(1, -1) and C(11, 4)
If the points P(-3, 9), Q(a, b) and R(4, -5) are collinear and a+b=1, find the value of a and b.
If the points A(1, 2), O(0, 0) and C(a, b) are collinear, then ______.
The points A(2, 9), B(a, 5) and C(5, 5) are the vertices of a triangle ABC right angled at B. Find the values of a and hence the area of ∆ABC.