मराठी

The Total Surface Area of a Hollow Metal Cylinder, Open at Both Ends of External Radius 8 Cm and Height 10 Cm is 338π Cm2. Taking R to Be Inner Radius, Write Down an Equation in R - Mathematics

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प्रश्न

The total surface area of a hollow metal cylinder, open at both ends of external radius 8 cm and height 10 cm is 338π cm2. Taking r to be inner radius, write down an equation in r and use it to state the thickness of the metal in the cylinder.

बेरीज

उत्तर

Surface area of the hollow cylinder = 338π cm2

2π(8)10 + 2π(r)10 + 2[ π(8)2 - π(r)2] = 338 π
⇒ 160 + 20r + 2(64 - r2) = 338
⇒  - 2r2 + 20r - 50 = 0
⇒  r2 - 10r + 25 = 0
⇒  (r - 5)2 = 0
⇒  r = 5

∴ Thickness of the metal in the cylinder = 8 - r = 8 - 5 = 3 cm.

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पाठ 17: Mensuration - Exercise 1

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आईसीएसई Mathematics [English] Class 10
पाठ 17 Mensuration
Exercise 1 | Q 25

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