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प्रश्न
The vector equation of a line passing through the point (1, –1, 0) and parallel to Y-axis is ______.
पर्याय
`vecr = hati - hatj + λ(hati-hatj)`
`vecr = hati - hatj+λhatj`
`vecr = hati - hatj + λhatk`
`vecr = λhatj`
MCQ
उत्तर
The vector equation of a line passing through the point (1, –1, 0) and parallel to Y-axis is `underlinebb(vecr = λhatj)`.
Explanation:
We know that vector equation of a line is
`vecr = veca+λvecb`
Given `veca=(1, -1, 0)`
passing through the point line is parallel to y-axis.
`vecb = (0, 1, 0)`
`vecr = hati - hatj + λhatj`
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