Question

The vector equation of a line passing through the point (1, –1, 0) and parallel to Y-axis is ______.

Options

• `vecr = hati - hatj + λ(hati-hatj)`

• `vecr = hati - hatj+λhatj`

• `vecr = hati - hatj + λhatk`

• `vecr = λhatj`

Answer 1

The vector equation of a line passing through the point (1, –1, 0) and parallel to Y-axis is `underlinebb(vecr = λhatj)`.

Explanation:

We know that vector equation of a line is

`vecr = veca+λvecb`

Given `veca=(1, -1, 0)`

passing through the point line is parallel to y-axis.

`vecb = (0, 1, 0)`

`vecr = hati - hatj + λhatj`