Advertisements
Advertisements
प्रश्न
The vertices of a ΔABC are A(3, 8), B(–1, 2) and C(6, –6). Find:
(i) Slope of BC
(ii) Equation of a line perpendicular to BC and passing through A.
उत्तर
A (3, 8) , B(–1, 2) , C(6, –6)
(i) Slope of BC = `(y_2 - y_1) /(x_2- x_1) = (-6 - 2)/(6-(-1)) = (-8)/7`
∴ Slope of BC = - `8/7`
(ii) Slope of line perpendicular to BC `= (-1)/((-8/7)) = 7/8`
Required line ⇒ y - y1 = m(x - x1 )
y - 8 = `7/8 (x-3)`
`8y - 64 = 7x -21`
`7x - 8y + 43 = 0`
APPEARS IN
संबंधित प्रश्न
State, true or false :
The point (8, 7) lies on the line y – 7 = 0
Find the equation of the line passing through : (−1, −4) and (3, 0)
Write down the equation of the line whose gradient is `-2/5` and which passes through point P, where P divides the line segement joining A(4, −8) and B(12, 0) in the ratio 3 : 1.
The line segment formed by the points (3, 7) and (-7, z) is bisected by the line 3x + 4y =18. Find the value of z.
The line segment formed by two points A (2,3) and B (5, 6) is divided by a point in the ratio 1 : 2. Find, whether the point of intersection lies on the line 3x - 4y + 5 = 0.
Find the inclination of a line whose gradient is 1.4281
Find the equation of a line passing through (2,9) and parallel to the line 3x + 4y = 11
Find the equation of a straight line which cuts an intercept of 5 units on Y-axis and is parallel to the line joining the points (3, – 2) and (1, 4).
If the image of the point (2,1) with respect to the line mirror be (5, 2). Find the equation of the mirror.
ABC is a triangle whose vertices are A(1, –1), B(0, 4) and C(– 6, 4). D is the midpoint of BC. Find the equation of the median AD.
