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प्रश्न
There are 30 cards, of same size, in a bag on which numbers 1 to 30 are written. One card is taken out of the bag at random. Find the probability that the number on the selected card is not divisible by 3.
उत्तर
Total no. of possible outcomes = 30 {1, 2, 3, … 30}
E ⟶ event of getting no. divisible by 3.
No. of favourable outcomes = 10 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) = 10/30 = 1/3
`barE`⟶ event of getting no. not divisible by 3.
P(`barE` ) = 1 – P(E)
= 1 - 1/3 = 2/3
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