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Question
There are 30 cards, of same size, in a bag on which numbers 1 to 30 are written. One card is taken out of the bag at random. Find the probability that the number on the selected card is not divisible by 3.
Solution
Total no. of possible outcomes = 30 {1, 2, 3, … 30}
E ⟶ event of getting no. divisible by 3.
No. of favourable outcomes = 10 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) = 10/30 = 1/3
`barE`⟶ event of getting no. not divisible by 3.
P(`barE` ) = 1 – P(E)
= 1 - 1/3 = 2/3
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