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Question
A box contains 30 tickets, bearing only one number from 1 to 30 on each. If one ticket is drawn at random, find the probability of an event that the ticket drawn bears an odd number .
Solution
Total number of tickets = 30
Number of tickets bearing odd number = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29
= 15
Therefore, required probability = `\text { Number of tickets bearing odd number}/text { Total number of tickets}`
`=15/30`
`=1/2`
Hence, the probability that the ticket drawn bears an odd number is `=1/2`.
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