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Question
A bag contains 3 red, 3 white and 3 green balls. One ball is taken out of the bag at random. What is the probability that the ball drawn is – either red or white.
Solution
Total number of balls = 3 + 3 + 3
= 9
Number of red and white balls = 3 + 3 = 6
Therefore, required probability = `\text { Number of red and white balls}/text { Total number of balls}`
= `6/9`
= `2/3`
Hence, the probability that a ball drawn is either red or white is `2/3`.
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