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Question
A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag. Find the probability that it bears a two digit number
Solution
Total no. of possible outcomes = 89 {2, 3, 4, …., 90}
Let E ⟶ event of getting a 2 digit no.
No. favourable outcomes = 81 {10, 11, 12, 13, ….., 80}
P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`= 81/89
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