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Question
Two dice (each bearing numbers 1 to 6) are rolled together. Find the probability that the sum of the numbers on the upper-most faces of two dice is more than 10.
Solution
When two dice are rolled, total number of possible outcomes = 36
Favorable outcomes for the sum of numbers more than 10 i.e. 11 or 12 are:
{(5, 6),(6, 5),(6, 6)}
Number of favorable outcomes = 3
P(getting a sum of numbers more than 10) = `3/36 = 1/12`
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