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Question
A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball the bag is twice that of a red ball, find the number of blue balls in the bag.
Solution
No of red balls = 6
Let no. of blue balls = x
Total no. of possible outcomes = 6 + x(total no. of balls)
P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(blue ball) = 2 P(red ball)
⇒ `x/(x+6) = (2(6))/(x+6)`
⇒ x = 2(6)
x = 12
∴ No of blue balls = 12
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