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Question
Tickets numbered from 1 to 20 are mixed up and a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 7?
Solution
Total no. of possible outcomes = 20 {1, 2, 3, …. , 20}
E ⟶ event of drawing ticket with no multiple of 3 or 7
No. of favourable outcomes = 8 which are {3, 6, 9, 12, 15, 18, 7, 14}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
=8/20 =2/5
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