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Question
A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random. What is the probability that ball drawn is not black?
Solution
Total no. of possible outcomes = 18 {6 red, 8 black, 4 white}
Let E ⟶ event of drawing black ball.
No. of favourable outcomes = 8 {8 black balls}
Probability, P(E) =`"no.of favorable outcomes"/"Total no.of possible outcomes"` =8/18 =4/9
`barE`⟶ event of not drawing black ball
𝑃`(barE)` = 1 − 𝑃(𝐸)
= 1 − (4/9) =5/9
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