Advertisements
Advertisements
प्रश्न
Two angles of an eight-sided polygon are 142o and 176o. If the remaining angles are equal to each other; find the magnitude of each of the equal angles.
उत्तर
Let the measure of each equal sides of the polygon is x.
Then we can write:
142° + 176° + 6 x = ( 2 x 8 - 4 ) 90°
6 x = 1080° - 318°
6 x = 762°
x = 127°
Thus the measure of each equal angles are 127°.
APPEARS IN
संबंधित प्रश्न
One angle of a six-sided polygon is 140o and the other angles are equal.
Find the measure of each equal angle.
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6° find the value of n.
Find the sum of the interior angles of a polygon of: 7 sides
Find each exterior angle of a regular polygon of: 18 sides
Find the number of sides in a regular polygon, when each interior angle is: 140°
Find the number of sides in a regular polygon, when each interior angle is: 135°
Find the number of sides in a regular polygon, when each exterior angle is: 20°
The ratio between the number of sides of two regular polygon is 3 : 4 and the ratio between their interior angles is 2 : 3. Find the number of sides of each polygon.
The number angle of a regular polygon is double the exterior angle. Find the number of sides of the polygon.
The sum of the interior angles of a polygon is 6.5 times the sum of its exterior angles. Find the number of sides of the polygon.
