Advertisements
Advertisements
प्रश्न
Two angles of an eight-sided polygon are 142o and 176o. If the remaining angles are equal to each other; find the magnitude of each of the equal angles.
उत्तर
Let the measure of each equal sides of the polygon is x.
Then we can write:
142° + 176° + 6 x = ( 2 x 8 - 4 ) 90°
6 x = 1080° - 318°
6 x = 762°
x = 127°
Thus the measure of each equal angles are 127°.
APPEARS IN
संबंधित प्रश्न
Two alternate sides of a regular polygon, when produced, meet at the right angle.
Find:
(i)The value of each exterior angle of the polygon;
(ii) The number of sides in the polygon.
AB, BC, and CD are the three consecutive sides of a regular polygon. If BAC = 15°;
Find:
- Each interior angle of the polygon.
- Each exterior angle of the polygon.
- The number of sides of the polygon.
Find the sum of the interior angles of a polygon of: 7 sides
Find the measure of each interior angle of a regular polygon of: 15 sides
Find each exterior angle of a regular polygon of: 15 sides
Find the number of sides in a regular polygon, when each interior angle is: 135°
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
The number of sides of two regular polygons are in the ratio 2 : 3 and their interior angles are in the ratio 9 : 10. Find the number of sides of each polygon.
Find the value of each angle of a heptagon If three of its angles measure 132° each and the remaining four.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
