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प्रश्न
Two beams of light having intensities I and 41 interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2 and π/3 at points A and B respectively. The difference between the resultant intensities at the two points is xl. The value of x will be ______.
पर्याय
1
2
3
4
MCQ
रिकाम्या जागा भरा
उत्तर
Two beams of light having intensities I and 41 interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2 and π/3 at points A and B respectively. The difference between the resultant intensities at the two points is xl. The value of x will be 2.
Explanation:
IA = I + 4I + 2`sqrt"I" sqrt(4"I")` cos `pi/2`
IA = 5I
and IB = I + 4I + 2`sqrt"I" sqrt(4"I") `cos`pi/3`
= 5I + 2I = 7I
IB - IA = 2I
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