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Two beams of light having intensities I and 41 interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2 and π/3 at points A and B respectively. -

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Question

Two beams of light having intensities I and 41 interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2 and π/3 at points A and B respectively. The difference between the resultant intensities at the two points is xl. The value of x will be ______.

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Solution

Two beams of light having intensities I and 41 interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2 and π/3 at points A and B respectively. The difference between the resultant intensities at the two points is xl. The value of x will be 2.

Explanation:

IA = I + 4I + 2`sqrt"I" sqrt(4"I")` cos `pi/2`

IA = 5I

and IB = I + 4I + 2`sqrt"I" sqrt(4"I")  `cos`pi/3`

= 5I + 2I = 7I

IB - IA = 2I

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