मराठी

Two identical heavy spheres are separated by a distance 10 times their radius. - Physics

Advertisements
Advertisements

प्रश्न

Two identical heavy spheres are separated by a distance 10 times their radius. Will an object placed at the mid point of the line joining their centres be in stable equilibrium or unstable equilibrium? Give reason for your answer.

टीपा लिहा

उत्तर

Let the mass and radius of each identical heavy sphere be M and A respectively. An object of mass m be placed at the mid-point P of the line joining their centres

Force acting on the object placed at the mid-point,

`F_1 = F_2 = (GMm)/(5R)^2`

The direction of forces is opposite, therefore net force acting on the object is zero. To check the stability of the equilibrium, we displace the object through a small distance x towards sphere A.

Now, the force acting towards sphere `A, F_1^' = (GMm)/(5R - x)^2`

Force acting towards sphere `B, F_2^' = (GMn)/(5R + x)^2`

As `F_1^' > F_2^'`, therefore a resultant force `(F_1^' - F_2^')` acts on the object towards sphere A, therefore, the object starts to move towards sphere A and hence equilibrium is unstable.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Gravitation - Exercises [पृष्ठ ६२]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 8 Gravitation
Exercises | Q 8.29 | पृष्ठ ६२
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×