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Two Long Bare Magnets Are Placed with Their Axes Coinciding in Such a Way that the North Pole of the First Magnet is 2.0 Cm from the South Pole of the Second. If Both the Magnets Have a Pole Strength - Physics

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प्रश्न

Two long bare magnets are placed with their axes coinciding in such a way that the north pole of the first magnet is 2.0 cm from the south pole of the second. If both the magnets have a pole strength of 10 Am, find the force exerted by one magnet of the other.

बेरीज

उत्तर

Given:
Pole strength = m1 = m2 = 10 Am
Distance between the north pole of the first magnet and the south pole of the second magnet, r = 2 cm = 0.02 m
We know,

Force (F) exerted by two magnetic poles on each other is given by

`F = u_0/(4pi) = (m_1m_2)/r^2`

= `(4pi xx 10^-7 xx 10^2)/(4pi xx 4 xx 10^-4)`

= `2.5 xx 10^-2  "N"`

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पाठ 14: Permanent Magnets - Exercises [पृष्ठ २७७]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 14 Permanent Magnets
Exercises | Q 2 | पृष्ठ २७७

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