मराठी

Urea is a very important nitrogenous fertilizer. Its formula is CON2H4. Calculate the percentage of nitrogen in urea. (C = 12, O = 16, N = 14 and H = 1). - Chemistry

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प्रश्न

Urea is a very important nitrogenous fertilizer. Its formula is CON2H4. Calculate the percentage of nitrogen in urea. (C = 12, O = 16, N = 14 and H = 1).

संख्यात्मक

उत्तर

Molar mass of urea; CON2H= 60 g

Weight of nitrogen in 1 g-molecule of CON2H4 = 28 g

So, % of Nitrogen = `28/60 xx 100`

= 46.66%

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Percentage Composition, Empirical and Molecular Formula
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पाठ 5: Mole concept and Stoichiometry - Exercise 5C [पृष्ठ ९१]

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सेलिना Concise Chemistry [English] Class 10 ICSE
पाठ 5 Mole concept and Stoichiometry
Exercise 5C | Q 19 | पृष्ठ ९१
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