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Question
Urea is a very important nitrogenous fertilizer. Its formula is CON2H4. Calculate the percentage of nitrogen in urea. (C = 12, O = 16, N = 14 and H = 1).
Solution
Molar mass of urea; CON2H4 = 60 g
Weight of nitrogen in 1 g-molecule of CON2H4 = 28 g
So, % of Nitrogen = `28/60 xx 100`
= 46.66%
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