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Question
Barium chloride crystals contain 14.8% water of crystallization. Find the number of molecules of water of crystallization per molecule.
Solution
Barium chloride = BaCl2. x H2O
Ba + 2Cl + x[H2 + O]
=137+ 35.5 + x [2+16]
=[208 + 18x] contains water = 14.8% water in BaCl2. x H2O
=[208 + 18 x] `14.8/100` = 18x
=[104 + 9x] 2148 =18000x
=[104 + 9x] 37 = 250x
=3848 + 333x = 2250x
1917x = 3848
x = 2 molecules of water
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