Advertisements
Advertisements
Question
In a compound of magnesium (Mg = 24) and nitrogen (N = 14), 18 g of magnesium combines with 7g of nitrogen.
Deduce the simplest formula by answering the following questions:
- How many gram-atoms of magnesium are equal to 18g?
- How many gram-atoms of nitrogen are equal to 7g of nitrogen?
- Calculate the simple ratio of gram-atoms of magnesium to gram-atoms of nitrogen and hence the simplest formula of the compound formed.
Solution
(a) G atoms of magnesium = `18/24` = 0.75 or `3/4` g-atoms
(b) G atoms of nitrogen = `7/14` = 0.5 or `1/2` g-atoms
(c) As calculated above,
Simplest ratio of `"g-atom of Mg"/"g-atom of N"`
= `(3/4)/(1/2)`
= `3/4 : 1/2`
∴ Mg : N = 3 : 2
∴ The simplest formula of the compound formed = Mg3N2
APPEARS IN
RELATED QUESTIONS
Ethane burns in oxygen to form CO2 and H2O according to the equation:
`2C_2H_6+7O_2 -> 4CO_2 + 6H_2O`
If 1250 cc of oxygen is burnt with 300 cc of ethane.
Calculate:
1) the volume of `CO_2` formed
2) the volume of unused `O_2`
Explain the terms empirical formula and molecular formula.
Give the empirical formula of C6H6.
Give example of compound whose:
Empirical formula is the same as the molecular formula.
Give example of compound whose:
Empirical formula is different from the molecular formula.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
A compound 'X' consists of 4.8% of C and 95.2% of Br by mass.
Determine the empirical formula of this compound.
[C = 12, Br = 80]
Find the percentage of mass water in Epsom salt MgSO4.7H2O.
Explain the term empirical formula.
A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correctly to 1 decimal place. (H = 1; \[\ce{C}\] = 12; \[\ce{Cl}\] = 35.5)