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Question
Determine the formula of the organic compound if its molecule contains 12 atoms of carbon. The percentage compositions of hydrogen and oxygen are 6.48 and 51.42 respectively.
Solution
| Element | Percentage weight | Atomic weight | No. of moles | Simple Ratio of atoms |
| H | 6.48 | 1 | `6.48/1` = 6.48 | `48.6/3.21` = 2 |
| O | 51.42 | 16 | `51.42/16` = 3.21 | `3.21/3.21` = 1 |
| C | 42.1 | 12 | `42.1/12` = 3.5 | `3.5/3.21` = 1 |
The empirical formula is CH2O
Since the compound has 12 atoms of carbon, so the formula is
C12H24O12.
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