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Question
An organic compound contains H = 4.07%, Cl = 71.65% chlorine and remaining carbon. Its molar mass = 98.96. Find its Empirical formula.
Solution
Mass of carbon = 100 − (4.07 + 71.65)
= 100 − 75.72
= 24.28%
| Element | Mass percentage | Atomic mass | Number of atoms | Simple ratio |
| C | 24.28 | 12 | `24.28/12` = 2 | `2/2` = 1 |
| H | 4.07 | 1 | `4.07/1` = 4 | `4/2` = 2 |
| Cl | 71.65 | 35.5 | `71.56/35.5` = 2 | `2/2` = 1 |
Empirical formula = CH2Cl
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