Advertisements
Advertisements
प्रश्न
Using suitable identities, evaluate the following.
101 × 103
बेरीज
उत्तर
We have,
101 × 103 = (100 + 1)(100 + 3)
= (100)2 + (1 + 3)100 + 3 × 1 ...[Using the identity, (x + a)(x + b) = x2 + (a + b)x + ab]
= 10000 + 400 + 3
= 10403
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३३]
APPEARS IN
संबंधित प्रश्न
Expand.
(p + 8) (p − 3)
Expand.
(9x − 5t) (9x + 3t)
Expand: (x + 2)(x + 3).
Expand: `(m + 3/2)(m + 1/2)`.
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(6a + 9)(6a – 5)
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(4x + 3y)(4x + 5y)
Evaluate the following, using suitable identity
51 × 52
(x + a)(x + b) = x2 + (a + b)x + ______.
Multiply the following:
(x2 – 5x + 6), (2x + 7)
Using suitable identities, evaluate the following.
104 × 97
