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प्रश्न
Using suitable identities, evaluate the following.
101 × 103
योग
उत्तर
We have,
101 × 103 = (100 + 1)(100 + 3)
= (100)2 + (1 + 3)100 + 3 × 1 ...[Using the identity, (x + a)(x + b) = x2 + (a + b)x + ab]
= 10000 + 400 + 3
= 10403
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३३]
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