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प्रश्न
Using suitable identities, evaluate the following.
104 × 97
योग
उत्तर
We have,
104 × 97 = (100 + 4)(100 – 3)
= (100)2 + (4 – 3)100 + 4 × (–3) ...[Using the identity, (x + a)(x + b) = x2 + (a + b)x + ab]
= 10000 + 100 – 12
= 10088
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३३]
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