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Question
Using suitable identities, evaluate the following.
104 × 97
Sum
Solution
We have,
104 × 97 = (100 + 4)(100 – 3)
= (100)2 + (4 – 3)100 + 4 × (–3) ...[Using the identity, (x + a)(x + b) = x2 + (a + b)x + ab]
= 10000 + 100 – 12
= 10088
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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 233]
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