Question

Volume of N₂ at NTP required to form a monolayer on the surface of iron catalyst is 8.15 ml/g of the adsorbent. If each nitrogen molecule occupies 16 × 10⁻²² m². The surface area of the 100 g adsorbent will be ______ × 10¹⁸ m².

पर्याय

• 20

• 35

• 50

• 60

Answer 1

Volume of N₂ at NTP required to form a monolayer on the surface of iron catalyst is 8.15 ml/g of the adsorbent. If each nitrogen molecule occupies 16 × 10⁻²² m². The surface area of the 100 g adsorbent will be 35 × 10¹⁸ m².

Explanation:

Total value = 8.15 × 100 ml = 815 ml

mole = `815/22400` = 0.036

∴ No. of molecules = 0.036 × 6.023 × 10²³ = 2.19 × 10²²

∴ Area required = 2.19 × 10²² × 16 × 10^–22 = 35 m²