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Volume of N2 at NTP required to form a monolayer on the surface of iron catalyst is 8.15 ml/g of the adsorbent. If each nitrogen molecule occupies 16 × 10−22 m2. -

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Question

Volume of N2 at NTP required to form a monolayer on the surface of iron catalyst is 8.15 ml/g of the adsorbent. If each nitrogen molecule occupies 16 × 10−22 m2. The surface area of the 100 g adsorbent will be ______ × 1018 m2.

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Solution

Volume of N2 at NTP required to form a monolayer on the surface of iron catalyst is 8.15 ml/g of the adsorbent. If each nitrogen molecule occupies 16 × 10−22 m2. The surface area of the 100 g adsorbent will be 35 × 1018 m2.

Explanation:

Total value = 8.15 × 100 ml = 815 ml

mole = `815/22400` = 0.036

∴ No. of molecules = 0.036 × 6.023 × 1023 = 2.19 × 1022

∴ Area required = 2.19 × 1022 × 16 × 10–22 = 35 m2

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