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प्रश्न
We wish to observe an object which is 2.5Å in size. The minimum energy photon that can be used ______.
पर्याय
5 KeV
8 KeV
10 KeV
12 KeV
MCQ
रिकाम्या जागा भरा
उत्तर
We wish to observe an object which is 2.5Å in size. The minimum energy photon that can be used is 5 KeV.
Explanation:
The wavelength of the waves must be of the same order of magnitude or smaller than the size of the object being viewed for scattering to occur. As a result, the maximum possible wavelength in the current issue is λmax = 2.5 Å.
Hence minimum energy is,
`E_{min} = hv_min = (hc)/max`
= `(12.40 xx 10^3)/(2.5Å)` eV.Å
= 4.96 × 103 eV
= 5 KeV
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The Photoelectric Effect
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