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Question
We wish to observe an object which is 2.5Å in size. The minimum energy photon that can be used ______.
Options
5 KeV
8 KeV
10 KeV
12 KeV
MCQ
Fill in the Blanks
Solution
We wish to observe an object which is 2.5Å in size. The minimum energy photon that can be used is 5 KeV.
Explanation:
The wavelength of the waves must be of the same order of magnitude or smaller than the size of the object being viewed for scattering to occur. As a result, the maximum possible wavelength in the current issue is λmax = 2.5 Å.
Hence minimum energy is,
`E_{min} = hv_min = (hc)/max`
= `(12.40 xx 10^3)/(2.5Å)` eV.Å
= 4.96 × 103 eV
= 5 KeV
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The Photoelectric Effect
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