Advertisements
Advertisements
प्रश्न
उत्तर
APPEARS IN
संबंधित प्रश्न
Name two factors on which the time period of a simple pendulum does not depend.
Calculate the time period of a simple pendulum of length 1.44 m on the surface of the moon. The acceleration due to gravity on the surface of the moon is 1/6 the acceleration due to gravity on earth, [g = 9.8 ms−2]
A pendulum of 100 cm and another pendulum 4 cm long are oscillating at the same time. Calculate the ratio of their time periods.
Write an expression for the time period of a simple pendulum.
Define the following in connection with a simple pendulum.
Effective length
Draw a graph of l, the length of simple pendulum against T2, the square of its time period.
State three important precautions which must be followed while plotting points on a graph.
Moon has no atmosphere and acceleration due to gravity at its surface is one-sixth that at the earth's surface. When a pendulum is taken from earth to moon surface, its time period will:
Define the following terms with reference to a simple pendulum:
Frequency
