Advertisements
Advertisements
प्रश्न
What happens when oxidation of tert-butylamine with KMnO4?
उत्तर
In general, primary amines, in which the –NH2 group is attached to a tertiary carbon can be oxidised with KMnO4 to the corresponding nitro compound in excellent yield.
Therefore 3°-butylamine oxidised to give 2-methyl-2-nitropropane.
\[\begin{array}{cc}
\phantom{...}\ce{CH3}\phantom{...................}\ce{CH3}\phantom{}\\
\phantom{}|\phantom{.......................}|\phantom{}\\
\ce{CH3 - C - NH2 ->[KMnO4] CH3 - C - NO2}\\
\phantom{}|\phantom{.......................}|\phantom{}\\
\phantom{........}\ce{\underset{(3°-butylamine)}{CH3}}\phantom{........}\ce{\underset{(2-methyl-2-nitropropane)}{CH3}}\phantom{..}
\end{array}\]
APPEARS IN
संबंधित प्रश्न
\[\ce{CH3CH2Br ->[aq NaOH][\Delta] A ->[KMnO4/H^+][\Delta] B ->[NH3][\Delta] C ->[Br2/NaOH] D}\] ‘D’ is:
Which of the following reaction is not correct.
Nitrobenzene on reaction with at 80-100°C forms which one of the following products?
What happens when 2-Nitropropane boiled with HCl?
How will you convert nitrobenzene into o and p-nitrophenol?
How will you convert nitrobenzene into azoxybenzene?
Write a short note on the following.
Hofmann’s bromide reaction
Account for the following.
Aniline does not undergo Friedel–Crafts reaction.
Account for the following.
Aniline does not undergo Friedel-Crafts reaction.
Account for the following:
Aniline does not undergo Friedel – Crafts reaction.