Question

What is the equivalent resistance across points A and B in the circuit given below?

 

पर्याय

• 8Ω

• 12Ω

• 16Ω

• 32Ω

Answer 1

8Ω

Explanation:

Given, resistances 10Ω and 2.5Ω are in parallel,

${\displaystyle R_1=\frac{10\times 2.5}{10+25}=2\Omega }$

Now, 2Ω and 10Ω are in series, R₂ = 10 + 2 = 12Ω

R₂ and 12Ω are in parallel, ${\displaystyle \frac{1}{R_3}=\frac{1}{12}+\frac{1}{12}}$

⇒ R₃ = 6Ω

Now, R₃ and 10Ω are in series, R₄ = 6 + 10 = 16Ω

Now, R₄ and 16Ω are in parallel.

${\displaystyle \frac{1}{R}=\frac{1}{16}+\frac{1}{16}\Rightarrow R=\frac{16}{2}=8\Omega }$

∴ Net equivalent resistance across points A and B is 8Ω.